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(25x^2)+17x-54=0
a = 25; b = 17; c = -54;
Δ = b2-4ac
Δ = 172-4·25·(-54)
Δ = 5689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{5689}}{2*25}=\frac{-17-\sqrt{5689}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{5689}}{2*25}=\frac{-17+\sqrt{5689}}{50} $
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